Optimal. Leaf size=135 \[ \frac {3 c (4 b B+A c) \sqrt {b x^2+c x^4}}{8 b x}-\frac {(4 b B+A c) \left (b x^2+c x^4\right )^{3/2}}{8 b x^5}-\frac {A \left (b x^2+c x^4\right )^{5/2}}{4 b x^9}-\frac {3 c (4 b B+A c) \tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {b x^2+c x^4}}\right )}{8 \sqrt {b}} \]
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Rubi [A]
time = 0.16, antiderivative size = 135, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 5, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.192, Rules used = {2063, 2045,
2046, 2033, 212} \begin {gather*} \frac {3 c \sqrt {b x^2+c x^4} (A c+4 b B)}{8 b x}-\frac {3 c (A c+4 b B) \tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {b x^2+c x^4}}\right )}{8 \sqrt {b}}-\frac {\left (b x^2+c x^4\right )^{3/2} (A c+4 b B)}{8 b x^5}-\frac {A \left (b x^2+c x^4\right )^{5/2}}{4 b x^9} \end {gather*}
Antiderivative was successfully verified.
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Rule 212
Rule 2033
Rule 2045
Rule 2046
Rule 2063
Rubi steps
\begin {align*} \int \frac {\left (A+B x^2\right ) \left (b x^2+c x^4\right )^{3/2}}{x^8} \, dx &=-\frac {A \left (b x^2+c x^4\right )^{5/2}}{4 b x^9}-\frac {(-4 b B-A c) \int \frac {\left (b x^2+c x^4\right )^{3/2}}{x^6} \, dx}{4 b}\\ &=-\frac {(4 b B+A c) \left (b x^2+c x^4\right )^{3/2}}{8 b x^5}-\frac {A \left (b x^2+c x^4\right )^{5/2}}{4 b x^9}+\frac {(3 c (4 b B+A c)) \int \frac {\sqrt {b x^2+c x^4}}{x^2} \, dx}{8 b}\\ &=\frac {3 c (4 b B+A c) \sqrt {b x^2+c x^4}}{8 b x}-\frac {(4 b B+A c) \left (b x^2+c x^4\right )^{3/2}}{8 b x^5}-\frac {A \left (b x^2+c x^4\right )^{5/2}}{4 b x^9}+\frac {1}{8} (3 c (4 b B+A c)) \int \frac {1}{\sqrt {b x^2+c x^4}} \, dx\\ &=\frac {3 c (4 b B+A c) \sqrt {b x^2+c x^4}}{8 b x}-\frac {(4 b B+A c) \left (b x^2+c x^4\right )^{3/2}}{8 b x^5}-\frac {A \left (b x^2+c x^4\right )^{5/2}}{4 b x^9}-\frac {1}{8} (3 c (4 b B+A c)) \text {Subst}\left (\int \frac {1}{1-b x^2} \, dx,x,\frac {x}{\sqrt {b x^2+c x^4}}\right )\\ &=\frac {3 c (4 b B+A c) \sqrt {b x^2+c x^4}}{8 b x}-\frac {(4 b B+A c) \left (b x^2+c x^4\right )^{3/2}}{8 b x^5}-\frac {A \left (b x^2+c x^4\right )^{5/2}}{4 b x^9}-\frac {3 c (4 b B+A c) \tanh ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {b x^2+c x^4}}\right )}{8 \sqrt {b}}\\ \end {align*}
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Mathematica [A]
time = 0.15, size = 114, normalized size = 0.84 \begin {gather*} -\frac {\sqrt {x^2 \left (b+c x^2\right )} \left (\sqrt {b} \sqrt {b+c x^2} \left (2 A b+4 b B x^2+5 A c x^2-8 B c x^4\right )+3 c (4 b B+A c) x^4 \tanh ^{-1}\left (\frac {\sqrt {b+c x^2}}{\sqrt {b}}\right )\right )}{8 \sqrt {b} x^5 \sqrt {b+c x^2}} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.38, size = 213, normalized size = 1.58
method | result | size |
risch | \(-\frac {\left (5 A c \,x^{2}+4 b B \,x^{2}+2 A b \right ) \sqrt {x^{2} \left (c \,x^{2}+b \right )}}{8 x^{5}}+\frac {\left (c B \sqrt {c \,x^{2}+b}-\frac {3 \ln \left (\frac {2 b +2 \sqrt {b}\, \sqrt {c \,x^{2}+b}}{x}\right ) A \,c^{2}}{8 \sqrt {b}}-\frac {3 c \sqrt {b}\, \ln \left (\frac {2 b +2 \sqrt {b}\, \sqrt {c \,x^{2}+b}}{x}\right ) B}{2}\right ) \sqrt {x^{2} \left (c \,x^{2}+b \right )}}{x \sqrt {c \,x^{2}+b}}\) | \(140\) |
default | \(-\frac {\left (x^{4} c +b \,x^{2}\right )^{\frac {3}{2}} \left (-A \left (c \,x^{2}+b \right )^{\frac {3}{2}} c^{2} x^{4}+3 A \,b^{\frac {3}{2}} \ln \left (\frac {2 b +2 \sqrt {b}\, \sqrt {c \,x^{2}+b}}{x}\right ) c^{2} x^{4}-4 B \left (c \,x^{2}+b \right )^{\frac {3}{2}} b c \,x^{4}+12 B \,b^{\frac {5}{2}} \ln \left (\frac {2 b +2 \sqrt {b}\, \sqrt {c \,x^{2}+b}}{x}\right ) c \,x^{4}+A \left (c \,x^{2}+b \right )^{\frac {5}{2}} c \,x^{2}-3 A \sqrt {c \,x^{2}+b}\, b \,c^{2} x^{4}+4 B \left (c \,x^{2}+b \right )^{\frac {5}{2}} b \,x^{2}-12 B \sqrt {c \,x^{2}+b}\, b^{2} c \,x^{4}+2 A \left (c \,x^{2}+b \right )^{\frac {5}{2}} b \right )}{8 x^{7} \left (c \,x^{2}+b \right )^{\frac {3}{2}} b^{2}}\) | \(213\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 1.45, size = 217, normalized size = 1.61 \begin {gather*} \left [\frac {3 \, {\left (4 \, B b c + A c^{2}\right )} \sqrt {b} x^{5} \log \left (-\frac {c x^{3} + 2 \, b x - 2 \, \sqrt {c x^{4} + b x^{2}} \sqrt {b}}{x^{3}}\right ) + 2 \, {\left (8 \, B b c x^{4} - 2 \, A b^{2} - {\left (4 \, B b^{2} + 5 \, A b c\right )} x^{2}\right )} \sqrt {c x^{4} + b x^{2}}}{16 \, b x^{5}}, \frac {3 \, {\left (4 \, B b c + A c^{2}\right )} \sqrt {-b} x^{5} \arctan \left (\frac {\sqrt {c x^{4} + b x^{2}} \sqrt {-b}}{c x^{3} + b x}\right ) + {\left (8 \, B b c x^{4} - 2 \, A b^{2} - {\left (4 \, B b^{2} + 5 \, A b c\right )} x^{2}\right )} \sqrt {c x^{4} + b x^{2}}}{8 \, b x^{5}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (x^{2} \left (b + c x^{2}\right )\right )^{\frac {3}{2}} \left (A + B x^{2}\right )}{x^{8}}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 0.97, size = 145, normalized size = 1.07 \begin {gather*} \frac {8 \, \sqrt {c x^{2} + b} B c^{2} \mathrm {sgn}\left (x\right ) + \frac {3 \, {\left (4 \, B b c^{2} \mathrm {sgn}\left (x\right ) + A c^{3} \mathrm {sgn}\left (x\right )\right )} \arctan \left (\frac {\sqrt {c x^{2} + b}}{\sqrt {-b}}\right )}{\sqrt {-b}} - \frac {4 \, {\left (c x^{2} + b\right )}^{\frac {3}{2}} B b c^{2} \mathrm {sgn}\left (x\right ) - 4 \, \sqrt {c x^{2} + b} B b^{2} c^{2} \mathrm {sgn}\left (x\right ) + 5 \, {\left (c x^{2} + b\right )}^{\frac {3}{2}} A c^{3} \mathrm {sgn}\left (x\right ) - 3 \, \sqrt {c x^{2} + b} A b c^{3} \mathrm {sgn}\left (x\right )}{c^{2} x^{4}}}{8 \, c} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {\left (B\,x^2+A\right )\,{\left (c\,x^4+b\,x^2\right )}^{3/2}}{x^8} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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